Question

A balloon is rising vertically
upwards with a constant velocity of 10 ms–1. When it is
at a height of 45 m above the ground, a stone is dropped
from it. Find the height of the balloon when the stone hits
the ground. Take g = 10 ms–2.​

Answer 1

Answer:

30

Explanation:

Given,

u=10m/s in upward direction.

g=−10m/s

2

in downward direction

t=3sec

H=45m

So by second equation of motion:

s=ut+

2

1

at

2

=10×3+

2

1

(−10)×3×3

=30−45

=−15m

Here negative sign indicates that it is directed downwards.

So height from the ground when he opened parachute is =45−15=30m

Answer 2

confused hu nhi toh bta deta