Question

A balloon is starting from the ground with an acceleration of 2 m/s². If a stone is dropped after 5 seconds, find the height of the balloon when the stone hits the ground. DO NOT POST RUBBISH ANSWERS

Answer 1

Answer:

Explanation:

v=at

v=10 m/s

s=ut+1/2at^2

s=-25 m

s=ut+1/2at^2

-25=10t - 5t^2

t^2-2t-5=0

t=6.9/2

t=3.45 sec

s=t^2

s=11.9025 m

height of the balloon when stone reaches ground =36.9025 m