A balloon starts rising from ground rest with an upward acceleration 2 m/secsqu. just after 1 sec. a stone is dropped from it the time taken by stone to strike the ground is nearly?
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HEIGHT ATTAINED BY BALLOON = HEIGHT FROM WHICH STONE COMES DOWN
IN CASE OF BALLOON
u = 0
t = 1 sec
a = 2m/sec ^2
s = ut + 1/2 at^2
s = 0 + 1
s = 1 m
IN CASE OF STONE
u = 0
s = 1 m
a = 9.8 m/sec^2
s = ut + 1/2 at^2
1 = 0 + 4.9 t ^2
t ^2 = 1/4.9
t^2 = 10 / 49
t = √10 / 7
ANSWER = √10 / 7
IN CASE OF BALLOON
u = 0
t = 1 sec
a = 2m/sec ^2
s = ut + 1/2 at^2
s = 0 + 1
s = 1 m
IN CASE OF STONE
u = 0
s = 1 m
a = 9.8 m/sec^2
s = ut + 1/2 at^2
1 = 0 + 4.9 t ^2
t ^2 = 1/4.9
t^2 = 10 / 49
t = √10 / 7
ANSWER = √10 / 7
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