Question

In an isosceles triangle ABC ,AB=AC=25 cm and BC=14 cm Then altitude from A on BC is=?

Answer 1

In triangle ABC
Let tge altitude be AD on BC

AC=25cm
AB=25cm
BC=14cm

Therefore DC= 1/2*BC
=1/2*14
=7

By Pythagoras theorem,
AD^2+CD^2=AC^2

AD^2+7^2=25^2

AD^2+49=625

AD^2=625-49

AD^2=576

AD=24

Therefore altitude from A on BC is 24 cm

Answer 2

Answer: here is your answer

.....

Dc is half 1/2 *bc

Which is 7

....

By phythagoras theorm,

Ad² + cd² = ac²

Ad²+7²=25²

Ad² = 576

Ad = 24

: altitude is 24