a balooln has a mass 10gm in air.the air escapes from the balloon at a uniform rate with a velocity 5m/s & the balloon shrinks completely in 2.5 sec.calculate the average force acting on the balloon
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Given:
mass=m=10gms=10/1000 kg=0.01kg
velocity=v=5m/s
t=2.5 sec
Formula:
Using second law of Motion:
F= d(mv)/dt
v is constant for this case.
so,
F=vdm/dt
=5x0.01/2.5
=0.02N
∴Force is 0.02N
mass=m=10gms=10/1000 kg=0.01kg
velocity=v=5m/s
t=2.5 sec
Formula:
Using second law of Motion:
F= d(mv)/dt
v is constant for this case.
so,
F=vdm/dt
=5x0.01/2.5
=0.02N
∴Force is 0.02N
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