Question

A,Band C are the angles of a triangle if A-B= 15 degree and B-C= 30 degree find angle A,B,C​

Answer 1

Answer:

angle A=A, angle B=B, angle C=C

given,

A-B=15°→A=15+B

B-C=30°→C=B-30

by angle sum property of triangle

A+B+C=180°

B+(15+B)+(B-30)=180

3B-15=180

3B=180+15

B=195/3

B=65°

So,

A=65+15=80°

B=65°

C=65-30=35°

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Answer 2

given A-B=15.

B-C=30

then A=15+B

B=30+C

ΔA+Δb+Δc=180

15+B+30+c+c=180

45 + 2c+B =180

45+2c+30+c=180

75+3c =180

3c=180-75

3c=105

c=105/3

therefore we get angle c=35

then

angle B= 30+c

B=30+35

B=65

angle A=15+B

A=15+65

A=80

there fore three angles are 80,65.35

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