A,band c together can do a piece f work in 40 days .After working with a,b and c for 16 days, a leaves and then b and c complete the remaining work in 40 days more.A alone could do the work in
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A,B,C can together do a work in 40 days. After working with B and C, A leaves after 16 days and the remaining work is completed by B and C in 40 days. In How many days A can work alone to finish the work?
Answer:-
Work done by A,B,C in 1 day
=
1
40
Work done by A,B,C in 16 days
=
16
40
=
2
5
Remaining work
=
1
−
2
5
=
3
5
.
This remaining work
3
5
is completed by B and C in 40 days.
Therefore work done by B and C in 1 day
=
(
3
5
)
40
=
3
200
Work done by A in 1 day
=
1
40
−
3
200
=
1
100
Therefore A alone can finish the work in 100 days.
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