Question

A bar magnet is oscillating in Earth's magnetic field with periodic time T. If a similar magnet with the same mass and volume has magnetic dipole moment, which is 4 times that of this magnet, then its periodic time will be _____ . (A) T/2
(B) 2T
(C) T
(D) 4T

Answer 1

Answer:

this question is of which class

Answer 2

Answer:

T₂ =  $\dfrac{T}{2}$

Explanation:

We have been given ,

       Time periodic= T

     Mass of the magnet  = m

Magnetic field is = B

Moment of inertia is = I

    Magnetic dipole moment is M₁ = M

     If magnetic dipole moment is M₂ = 4 M

Now ,

Therefore we know that

$\dfrac{T1}{T2} =\sqrt{\dfrac{M2}{M1} } \\\\\dfrac{T}{T2} = \sqrt{\dfrac{4M}{M} }$

Time of oscillation is T₂ =  $\dfrac{T}{2}$

Correct answer is T₂ =  $\dfrac{T}{2}$