Question

A bar magnet of length 10cm and pole strength 20A−m is deflected through 30o from the magnetic meridian. If earths horizontal component field is 320/4π × A/m . The moment of the deflecting couple is:

Answer 1

Answer:

It is given that length of bar magnet L=10cm=0.1m

pole strength m=20A-m

earths horizontal component field Bh=320/4pi Am^-1

Torque T=MB sin theta

T=mlBsin theta

T=20×0.1×320/4pi ×sin 30

T=25.4Nm.

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Answer 2

Answer:

It is given that length of bar magnet L=10cm=0.1m

Pole strength m=20A−m

earths horizontal component field B

H

=

4π

320

Am

−1

torqueτ=MBsinθ

τ=mlBsinθ

τ=20×0.1×

4π

320

×sin30

τ=25.4Nm

Explanation:

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