Question

A barometer is taken to a mountain from sea level. A fall 5 cm of mercury height is observed. If average density of air is 1.30 kgm$^{–3}$ and that of mercury is 13600 kgm$^{–3}$, calculate how high the barometer is taken. (g = 10 ms$^{–2}$​)

Answer 1

$\underline {Given:}$

• A fall 5 cm of mercury height is observed.
• Average density of air is 1.30 kgm$^{–3}$
• Average density of mercury is 13600 kgm$^{–3}$

$\underline {To\:Find:}$

Height to which the barometer is taken.

$\underline {Solution:}$

From the given question it is clear that fall of pressure due to mercury = Fall of pressure due to air

$\implies$ $h_{mercury}$ × $d_{mercury}$ × g = $h_{air}$ × $g_{air}$ × g

= 5/100 (m) × 13600 (kgm$^{–3}$) × g

= $h_{air}$ × 1.30 (kgm$^{–3}$)

By doing further calculation, $h_{air}$ =

$\frac{5 \times 13600}{100 \times 1.30} m \: \: = 523.0 \: m$

So, height to which barometer is taken = 523 m.

Answer 2

Answer:

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