A barrel contains 150 l of pure wine.30l of wine is replaced by water.This process is repeated for two more times. Find the quantity of wine in the resultant solution
Answers
Answer:For such type of questions where milk is taken out and replaced with water and this process is repeated many times,
Then we solve these questions as-
Fraction of milk in solution- ((x-y)/x)^n
Where,
x = quantity of solution
y = quantity of milk replaced by water
n = number of times the procedure is repeated
And
Quantity of milk in solution = x * fraction of milk in solution
( x is defined above)
Therefore in the given question-
x=40 , y= 4 , n=3
Hence quantity of milk= 40 * ((40-4)/40)^3
= 29.16
Step-by-step explanation:
Answer:
Answer:For such type of questions where milk is taken out and replaced with water and this process is repeated many times,
Then we solve these questions as-
Fraction of milk in solution- ((x-y)/x)^n
Where,
x = quantity of solution
y = quantity of milk replaced by water
n = number of times the procedure is repeated
And
Quantity of milk in solution = x * fraction of milk in solution
( x is defined above)
Therefore in the given question-
x=40 , y= 4 , n=3
Hence quantity of milk= 40 * ((40-4)/40)^3
= 29.16
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Step-by-step explanation: