Math, asked by iamrosie1202, 5 months ago

a baseball diamond is a square that is 90 feet on each side. What is the distance a catcher has to throw the ball from home to second base. (using pythagorean theorem)

Answers

Answered by angeleatpotato11800

Answer:

Step-by-step explanation:

Notice that the distance from home to second base is a diagonal of the square, which can be found using pythagorean theorem where the diagonal is the hypotenuse and both legst are 90 feet long. Therefore, the distance a catcher has to throw the ball from home to second base is around 127.3 feet.

Answered by anjanettemc904

Answer:127.3

Step-by-step explanation:

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