Question

Solve 37-(3x+5) ≥9x-8(x-3).​

Answer 1

Solution:

• 37 -(3x + 5) ≥ 9x -8(x - 3)

On simplifying;

We get:

$\implies$ 37 – 3x – 5 ≥ 9x – 8x + 24

$\implies$ 32 – 3x ≥ x + 24

On rearranging;

$\implies$ 32 – 24 ≥ x + 3x

$\implies$ 8 ≥ 4x

$\implies$ 2 ≥ x

All the real numbers of x which are less than or equal to 2 are the solutions of the given inequality.

Hence,

• (- ∞, 2) is the Solution for the given inequality.