A baseball goes from zero to 44 m/s in 0.153 s. What is its average acceleration?
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Here ..
u = 0
v = 44m/s
t = 0.15 second
a = ?
Now, we know
a =( v-u ) / t
a = (44-0)/0.15
a = 44/0.15
a = 44/15/100
a = 4400/15
a = 293.33
Therefore , acceleration = 293.34 (approx ) m/s^2 ...!!
u = 0
v = 44m/s
t = 0.15 second
a = ?
Now, we know
a =( v-u ) / t
a = (44-0)/0.15
a = 44/0.15
a = 44/15/100
a = 4400/15
a = 293.33
Therefore , acceleration = 293.34 (approx ) m/s^2 ...!!
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