Question

A basket contain 6 blue,2 red ball,4 green ball , and 3 yellow balls.If 3 balls are picked at random, what is the probability that none is yellow

Answer 1

Answer:

12/15 = 4/5 is the probability for the yellow not having.

Answer 2

Answer:  

Probability that none is yellow balls is$\frac{44}{91}$.

Given Data:

6 blue balls

2 red balls

4 green balls

3 yellow balls.

3 balls are picked randomly.

To find:

Probability (None is yellow)?

Step 1:

Total number of balls n(s) = 6+2+4+3=15 balls

Step 2:

S=3 balls are picked randomly= $15 \mathrm{C}_{3}$

$=\frac{15 \times 14 \times 13}{3 \times 2 \times 1}$

$=\frac{2730}{6}$

S = 455

Step 3:

E (Non yellow balls) = total number of balls – yellow balls.

E = 15 – 3

E = 12

P $=\frac{E}{S}=\frac{12 \times 11 \times 10}{15 \times 14 \times 13}=\frac{44}{91}.$