Question

a basket contains 10 apples and 20 oranges out of which 3 apples and 5 oranges are defective. if we choose two fruits at random, what is the probability that either both are oranges or both are non defective?

Answer 1

it will beorange because oranges are more in number

Answer 2

Answer:

Step-by-step explanation:

Here total no of fruits are 30

So in question they asked to select 2 fruits

Therefore n(S)=30C2

P(A) =20C2/30C2 as P(A) is the 2 fruits selected from oranges

P(B) =22C2/30C2 as P(B) is the 2 fruits selected from non defected fruits

P(A intersection B)= 15C2/30C2 as it indicated only oranges that ie Non defected-Defected ie20-15 and drawn to fruits from them

So P(A union B)=p(A)+P(B)-P(A intersection B)

=20C2/30C2 + 22C2/30C2 - 15C2/30C2 = 316/435