a basket contains some yellow red and blue balls there are 15 yellow and red balls there are 18 red and blue balls total number of blue and yellow balls is 9 find number of balls for each colour
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red ball be x
yellow balls be y
blue balls be z
So according to the conditions
x + y =15 ----(1)
x + z = 18 -------(2)
y + z = 9 ----------(3)
adding these 3 equations
2x + 2y + 2z = 42
2(x + y + z )= 42
x + y + z = 21 ----(4)
from --- (1) putting value in (4)
15 + z =21
z = 21 - 15
z = 6
putting in ---(2)
x + z =18
x + 6 =18
x= 18 -6
x = 12
putting in eq.(1)
x + y = 15
12 + y =15
y =15 - 12
y = 3
answer
x = red ball = 12
y = yellow ball = 3
z = blue ball= 6
Answered by
0
Answer:
Yellow(y) =3
Red(r)=12
Blue(b)=6
Step-by-step explanation:
y+r=15
r+b=18
b+y=9
Adding,
2(y+r+b)=42
y+r+b=21
Therefore, b=21-15=6
y=21-18=3
r=21-9=12
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