A basket has two types of fruits containing 20 apples and 3 oranges what percent of total no. of fruits to the number of oranges in the basket
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13.0434782609 %
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Solution :
Let A denotes Apples and O denotes Oranges and it is given that there are 20 apples and 10 oranges.
Out of 20 apples 5 and 10 oranges 3 are defective.
P(AUB)=P(A)+P(B)−P(A∩B)P(AUB)=P(A)+P(B)-P(A∩B)
n(A)=(20C2)n(A)=(20C2)
P(A)=20C230C2P(A)=20C230C2
n(B)=22C2n(B)=22C2
P(B)=22C230C2P(B)=22C230C2
n(A∩B)=15C2n(A∩B)=15C2
P(A∩B)=15C230C2P(A∩B)=15C230C2
P(AUB)=20C230C2+22C230C2−15C230C2P(AUB)=20C230C2+22C230C2-15C230C2
P(AUB)=0.72
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