A basketball court 28 m by 15m is surrounded by a path of uniform width 2.5m. find the area of the path
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Answer : 240sqm
Area of the path = (area of basketball court + area of path)- area of basketball court.
=[(28m+2.5m+2.5)*(15m+2.5m+2.5)]-28 m*15m
=(28m + 5m) * (15m + 5m) - 28m * 15m
=(33m * 20m) - (28m * 15m)
=660sqm - 420sqm
=240sqm
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