Question

A bathroom is 4m long 3.5 m broad and 3m high. Find the cost of laying tiles in its floor and four walls at the rate of 100 per m^2

Answer 1

Step-by-step explanation:

Area of floor = 4×3.5 =14m^2

Area of walls =2×3.5×3+2×4×3

= 21+24= 45m^2

Thus total area 59m^2

Cost = 100 ×59= 5900

Hope it helps ✌️✌️✌️

Answer 2

$\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}$

${\boxed{\sf\:{Dimensions\;are :- }}}$

Length = 4 m

Breadth = 3.5 m

Height = 3 m

Now,

${\boxed{\sf\:{Area\;of\;the\;floor\;(N1)}}}$

= length × breadth

= 4m × 3.5 m

= 14 m²

Now,

${\boxed{\sf\:{Area\;of\;4\;walls\;(N2)}}}$

= 2( l + b )h

= 2(4m + 3.5m) × 3

= 2 × 7.5 × 3

= 45 m²

Now,

${\boxed{\sf\:{Total\;area\;of\;laying\;tiles}}}$

= N1 + N2

= 14 m² + 45 m²

= 59 m²

Therefore

${\boxed{\sf\:{Cost\;of\;tiles\;1m^2 =100}}}$

${\boxed{\sf\:{Cost\;laying\;tiles\;59m^2}}}$

= 100 × 59

= 5900