A batsman deflect a ball by an angle of 45 without changing its initial speed which is equal to 54km per hour. What is the impulse imparted to the ball mass of the ball is 0.15 kg
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calculate change in momentum.
p1=p2 = .15× 15=2.25 kg m/s
Now using parallelogram law of vector addition
delta p= under the root(p1 square + p2 square+ 2 p1.p2 cos 45)= answer
p1=p2 = .15× 15=2.25 kg m/s
Now using parallelogram law of vector addition
delta p= under the root(p1 square + p2 square+ 2 p1.p2 cos 45)= answer
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