A batsman deflects a ball by an angle of 45 degree without changing its initial speed which is equal to 54 km h-1 what is the impulse imparted to be the ball when the mass of the ball is 0.15 kg
Answers
Answered by
2
here is your answer please mark me as brainlist! please
Attachments:
Answered by
0
Answer:
Explanation:
Answer- 4.16 kgm/s
## Explaination-
# Given-
m = 0.15 kg
v = 54 km/h = 15 m/s
θ = 45°
# Solution-
Assume, vector A be the angle bisector of the ball path such that it makes angle of θ/2 with both initial & final path.
Now, initial momentum is given by,
pi = m×u×cos(θ/2)
Also, final momentum is given by,
pf = -m×u×cos(θ/2)
Impulse = Change in momentum
I = pf-pi
I = m×u×cos(θ/2) + m×u×cos(θ/2)
I = 2×m×u×cos(θ/2)
Putting values,
I = 2×0.15×15×cos22.5°
I = 4.157 kgm/s
Impulse imparted to the ball is 4.157 kgm/s
Similar questions