A batsman deflects a ball by an angle of 45° without changing its initial speed which is equal to 54 km/h. What is the impulse imparted to the ball? (Mass of the ball is 0.15 kg.)
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Explanation:
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Velocity of ball u=54 km/h=54×
18
5
=15 m/s
The ball struck by the bat is deflected back such that,
Total angle =45
0
Now the initial momentum of the ball is mucosθ=
3600
0.15×54×1000×cos22.5
=0.15×15×0.9239 along NO,
FInal momentum of the ball is mucosθ Along ON,
Thus Impulse is equal to the change in momentum,
=mucosθ−(−mucosθ)=2mucosθ=2×0.15×15×0.9239=4.16kgm/s
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