Question

a batsman deflects a ball by an angle of 90 degree without changing its initial speed which is equal to 54 km per hour what is the impulse imparted to the ball

Answer 1

hope 9.......but not sure

Answer 2

Given,

Mass of the ball m=0.15kg.

The initial speed of the ball u=

$54km/h= \frac{54 \times 1000}{60 \times 60}$

The final speed of the ball vf=ucos45⁰

The momentum change takes place in the ball in the vertical direction only because the initial and final momentum in the horizontal direction is canceled out.

vi=−ucos45

According to the impulse-momentum theorem,

Impulse=Changeinmomentum

$⇒I=m(v_f−v_i)$

$I=mucos45^0−(−mucos45^0)$

$I=2mucos45^0$

Substitute the value of mass and velocity.

I=2×0.15×15×0.7071

I=3.19kgm/s