Question

solve it please.....

Answer 1

The answer to the 12th question is

$x = {t}^{2 \div 3} + 4 {t}^{ - 1 \div 2}$
substitute the value of t=64

$x = {64}^{2 \div 3} + 4 \times {64}^{ - 1 \div 2}$
x= 16+ 4(1/8)

x= 16.5.


hope this helps

Answer 2

your 12th no . answer is A 3/2
and 11th no. answer is C 33/2