Math, asked by ipsitasahoo, 1 year ago

solve it please.....

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Answers

Answered by sucheth

The answer to the 12th question is

$x = {t}^{2 \div 3} + 4 {t}^{ - 1 \div 2}$
substitute the value of t=64

$x = {64}^{2 \div 3} + 4 \times {64}^{ - 1 \div 2}$
x= 16+ 4(1/8)

x= 16.5.

hope this helps

ipsitasahoo: can you please explain me 64^2/3 =16 how

ipsitasahoo: and also 64 ^-1/2

Answered by rajiv3215

your 12th no . answer is A 3/2
and 11th no. answer is C 33/2

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ipsitasahoo: please explain the no 12

rajiv3215: ok

rajiv3215: i hope you will understand

rajiv3215: is my answer right?

ipsitasahoo: thank you so much

ipsitasahoo: yes right

rajiv3215: most welcome

ipsitasahoo: no 15 kardoge

rajiv3215: haa phle question to dijiye

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