Question

A batsman hits back a ball of mass 0.15 kg straight in the direction
of the bowler without changing its initial speed of 10 ms-1. If the ball
moves linearly, then the impulse imparted on it is
(a) 3.0
(b) 2.0
(c) 1.5
(d) 1.9​

Answer 1

Hi mate

Question

A batsman hits back a ball of mass 0.15 kg straight in the direction

of the bowler without changing its initial speed of 10 ms-1. If the ball

moves linearly, then the impulse imparted on it is

(a) 3.0

(b) 2.0

(c) 1.5

(d) 1.9

Answer:

Option (a) 3.0 is your answer

Kindly refer the attachment

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Answer 2

Given: A batsman hits back a ball of mass 0.15 kg straight in the direction of the bowler without changing its initial speed of 10 m/s.

To find: Impulse imparted on it

Explanation: Mass of ball= 0.15 kg

Initial velocity of the ball= 10 m/s

Final velocity of the ball= -10 m/s since the ball is in exactly the opposite direction

Initial momentum= Mass* Initial velocity

= 0.15 * 10

= 1.5 kg m/s

Final momentum= Mass* Final velocity

= 0.15 * -10

= -1.5 kg m/s

Change in momentum= Initial momentum- Final

momentum

=> Change = 1.5- (-1.5)

= 3 kg m/s

Impulse imparted is equal to the change in momentum of the ball after it is hit by the batsman.

Therefore, the impulse imparted is option (a) 3 kg m/s.