Question

A batsman hits back a ball of mass 0.15 kg straight in the direction of the bowler without changing its initial speed of 12 ms–1. if the ball moves linearly, then the impulse imparted to

Answer 1

impulse= force ×time= rate of change of momentum= m(v-u)
so impulse=0.15(0-12)
impulse=12×0.15 =1.8 Ns

Answer 2

${\huge{\underline{\underline{\mathfrak{\purple{♡ANSWER♡}}}}}}$.

✪. Change in momentum=${0.15×12-(-0.15×12)}$

✪. ${3.6Ns,}$

✪. $\red{\bold{\underline{\underline{Impulse}}}}$ = ${3.6Ns,}$

• In the direction from the batsman to the bowler .
• This is an example where the force on the ball by the batsman and the time of contact of the ball and the bat are difficult to know , but the impulse is readily calculated