a batsman hits back a ball straight in the direction of a bowler without changing its initial speed of 12 m per second if the mass of the ball is 0.15 kilogram determine the impulse imparted to the ball
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Impulse (J) = Force (F) × time (t) = Change in Momentum (∆p)
u = - 12 m/s
v = 12 m/s
m = 0.15 kg
∆p = m(v - u)
J = 0.15 kg (12 -(- 12)) m/s
J = 0.15 kg × 24 m/s
J = 3.6 kg·m/s.
u = - 12 m/s
v = 12 m/s
m = 0.15 kg
∆p = m(v - u)
J = 0.15 kg (12 -(- 12)) m/s
J = 0.15 kg × 24 m/s
J = 3.6 kg·m/s.
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✪. Change in momentum=
✪.
✪. =
- In the direction from the batsman to the bowler .
- This is an example where the force on the ball by the batsman and the time of contact of the ball and the bat are difficult to know , but the impulse is readily calculated
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