a batsman in his 11th Ganesh make a score of 68 and thereby increases his average score by 2 what is his average score after the 11th innings
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Answered by
30
Correct question be :
A batsman in his 11th innings make a score of 68 and thereby increases his average score by 2 what is his average score after the 11th innings?
Solution :
Let us take in first 10 innings, his total runs was x
Then , average in 1st 10 innings = x/10
Given that, (x + 68)/11 = (x/10) +2
==> (x + 68)/11 = (x + 20)/10
==> 10 (x + 68) = 11 (x + 20)
==> 10x + 680 = 11x + 220
==> 11x - 10x = 680 - 220
==> x = 460
Total score in 1st 10 innings = 460
So, his total score after 11th innings
= 460 + 68 = 528
Average score be
= (460/10) + 2 = 46 + 2 = 48
Anonymous:
superb
Answered by
25
ANSWER:--
{let the runs be {X}
{So,let the total score after 10 innings = 10x runs.}
{Score in 11th innings = 68 runs.}
{11th innings = 10x+68 runs.}
here,are the following steps follows the solution to this problem
{ 11 innings = (10x+68)/11
={ x+2 .}
{11 × (x+2)= 10x + 68
{x = 46}
{let the Average score of the innings= x+2 = 48 runs}
hope it helps:--
T!—!ANKS!!!!
Aim for 20+(T!—!ANKS)
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