Math, asked by amarjitkumarsingh63, 11 months ago

A batsman in his 12th innings make, a score of 63 runs and thereby increases, his average score by 2 . What is his average score after the 12th innings?​

Answers

Answered by ihrishi
8

Step-by-step explanation:

Let the average score of 11th inning be x.

Therefore, after 12th inning,

Average score = x + 2

Total runs scored in 11 innings = 11x

Average \:  score  \: of  \: 12^{th}   \: inning  \\   \\ =  \frac{11x + 63}{12}  \\   \\ \therefore \: x + 2 =  \frac{11x + 63}{12}  \\  \\  \therefore \: 12(x + 2) = 11x + 63 \\  \\ \therefore \: 12x + 24= 11x + 63 \\ \\  \therefore \: 12x  - 11x= 63 - 24 \\ \\  \therefore \: x= 39 \\ \\  \implies \: x + 2 = 39 + 2  \\   \huge \purple{ \boxed{\implies \: x + 2 = 41}}

Thus, average score after 12th inning is 41 runs.

Answered by ankitchaudhary181
1

Answer:

Above answer is correct

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