Question

A batsman makes a score of 111 runs in the 10th match and thus increases his average runs per match by 5. what will be his average after the 10th match?

Answer 1

As per the question he has played 9 matches so far,
So let the average of that batsman for 9 matches be x

Now,
Average= (Total runs scored)/(Total number of matches)
So,
Total number of runs scored in 9 matches = 9x
Now, he scores 111 in the 10th match 
So,
Total runs scored = 111+9x
After the 10th match his average increases by 5
So,
Average = x+5
Now equating the terms,
(111+9x)/10  =  x + 5
111+9x = 10x + 50
x=61
So,
Average for 9 matches was 61 after 10th match average
= 61+5=66

So, 66 will be his average

Answer 2

Answer:

Step-by-step explanation:

Avg runs scored in this tournament so far:182

Runs scored in the last H2H match:162