A batter hits a ball and it is caught 4 seconds later 100 m from home plate. What is the initial velocity (vector!!!) of the ball? (Note: the ball is hit and caught at the same distance from the ground.
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Answer:
the answer is 50 ms-¹
Explanation:
we know that s= ut + ½at²
now, s=100m
u= 0ms-¹
t= 4s
so 100= 0×4+ ½a (4)²
or, 0+ 8a= 100
or, a= 100÷8
or, a= 12.5
now, v= u+ at
so v= 0 + 12.5× 4
or, v= 50
hope it helps
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