Physics, asked by harshita19pandey, 11 months ago

A battery connected with the resistor in series . If the voltage of 1 resistor is 9 volt what is the voltage across the other resistor?​

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Answered by MilanKumar17
4

Answer:

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Answered by gumnaambadshah
19

Answer:

As we know battery supplied voltage = E - Ir

Where E is the EMF of cell , I is the current passing through battery and r is internal resistance of battery . Putting all the values we get

8=9-5×r

=> r=1/5 =0.2 ohmAs we know battery supplied voltage = E - Ir

Where E is the EMF of cell , I is the current passing through battery and r is internal resistance of battery . Putting all the values we get

8=9-5×r

=> r=1/5 =0.2 ohmAs we know battery supplied voltage = E - Ir

Where E is the EMF of cell , I is the current passing through battery and r is internal resistance of battery . Putting all the values we get

8=9-5×r

=> r=1/5 =0.2 ohmAs we know battery supplied voltage = E - Ir

Where E is the EMF of cell , I is the current passing through battery and r is internal resistance of battery . Putting all the values we get

8=9-5×r

=> r=1/5 =0.2 ohm..

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