Physics, asked by Zabed4, 8 months ago

A battery has an emf É and an internal resistance r. It is connected to an external resistor R. When R = 4.5 Ω the terminal potential difference is 9.952 V. When R = 8Ω the terminal potential difference is 10.575 V. Find É and r.

Answers

Answered by 138412
0

Answer:

Here's your answer.

Explanation:

Total resistance of the circuit R

eq

=R+r

Current in the circuit I=

R

eq

E

=

R+r

E

Thus potential difference across the battery V=IR=

R+r

ER

As R→0, we get V→0.

Also I=

r

E

for R→0.

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