Question

A battery of 12 V is connected to a series
combination of resistors 3 ohm,4 ohm,5 ohm and 120
How much current would low through the 12W resistor ?​

Answer 1

v = 12v

R =3+4+5+120= 132ohm

i = 12/132

v in 12 ohm resistor = iR = 144/132

so i = 12/132 A

Answer 2

Answer:

V= 12V

R= 3+4+5+120

= 132 Ω

I = 12/132

V in 12 ohm resistor= IR

=144/132

=12/132