A battery of 15 volts is connected to a parallel group of resistance of 4,10 and 20 ohm. Find the current in the circuit
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we have,
R1=4&r2,=10 and r3=20
by ohms law we get
v = ir
R = 4+10+20=34
15=34×i
I=34/15
R1=4&r2,=10 and r3=20
by ohms law we get
v = ir
R = 4+10+20=34
15=34×i
I=34/15
pragatikapoor58:
Your awnser is incorrect because the resistors are connected in parallel and u are adding them as if they are connected in series
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12
I hope the answer is correct....
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