Question

A battery of 6 volt is connected to the
terminals of a three metre long wire of
uniform thickness and resistance of the order
100 ohm. The difference of potential between
two points separated by 50 cm on the wire
will be :​

Answer 1

Answer:

A 6 V battery is connected to the terminals of a 3 m long wire of uniform thickness and resistance of 100Ω. The difference of potential between two points on the wire separated by a distance of 50 cm will be. Solution : Voltage on 50 cm =6300×50=1 volt

Hope this will help you..

Answer 2

Explanation:

potential drop across 1cm = 6/300

potential drop across 50 cm =( 6 x 50 )/300

= 1V.