Question

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ω and 12 Ω,
respectively. How much current would flow through the 12 Ω resistor?
[Try to solve these problems and write in your note book)

Answer 1

Answer:

0.671 A

Explanation:

There is no current division occurring in a series circuit. Current flow through the component is the same.

Resistances are connected in series. Hence, the sum of the resistances will give the value of R. R = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 Ω

Potential difference, V = 9 V

I = V = 9V = 0.671 A

R 13.4Ω

∴ the current that would flow through the 12 Ω resistor will be 0.671 A.

Answer 2

Answer:

It is the correct answer.

Step-by-step explanation:

Hope this attachment helps you.