A battery of 9 V is connected in series with resistors of 0.2 ohm, 0.3 ohm, 0.4 ohm, 0.5 ohm and 12 ohm respectively. How much current would flow through the 12 ohm resistor?
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Secondary SchoolScience 8+4 pts
A battery of 9v is connected in series with resistors of 0.2 ohm, 0.3ohm, 0.4ohm, 0.5ohm and 12ohm respectively. how much current would flow through 12ohm resistor
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Report by K1avikanitaruchini 09.06.2016
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prmkulk1978
Prmkulk1978 Brainly Guru
Given
Battery=9V
resistors of 0.2 ohm, 0.3ohm, 0.4ohm, 0.5ohm and 12ohm are connected in series to battery.
R1=0.2ohm
R2=0.3ohm
R3=0.4ohm
R4=0.5ohm
R5=12ohm
As all are connected in series effective resistance would be :
Reff=R1+R2+R3+R4+R5
=0.2+0.3+0.4+0.5+12
=13.4OHMS
By ohms law : V=IR
I=V/R
=9/13.4
=0.67 A
As resistors are connected in series. I=I1=I2=I3=I4=I5
Hence current across 12ohms resistor is 0.67A
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Answered by
6
current = V/R
V = 9
R = 12
I = 9/12
= 0.75 A
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