Question

A battery of 9 V is connected in series with resistors of 0.2 Ω. 0.3 Ω 0.4 Ω , 0.5 Ω and 12 Ω respectively. How much current would flow through the 12 Ω resistor?

Answer 1

R=12 ohms.
V=9 V.
I=(V/R).
I=(9/12).
I=0.75 A.

Answer 2

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Total resistance of resistors when connected in series is given by

= 1 + 2 + 3 + 4 + 5

= 0.2 Ω+ 0.3 Ω+ 0.4 Ω+ 0.5 Ω+ 12 Ω = 13.4 Ω

According to Ohm’s law,

V = IR

I =V/R

I = 9 /13.4 = 0.67

▶▶There is no current division occurring in a series circuit.

So, the current through the 12 Ω resistor will be same as 0.67 A.

I hope, this will help you___❤❤

Thank you

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