Physics, asked by nathanchetna5821, 1 year ago

A battery of emf 10 volt and internal resistance 3 ohm is connected to a resistor the current in circuit is

Answers

Answered by ferozemulani
1

Explanation:

emf = (current * internal resistance)

10 = ( i * r)

where i = current

r= internal resistance

10 = (i * 3)

therefore i = (10/3)

i = 3.33 ampere

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