Question

A boy dropped a ball from the top of 20 m building and starts the stopwatch. What will be the reading of
stopwatch when ball will reach at ground surface, if acceleration due to gravity is 10 m/s??​

Answer 1

Answer:

Since it has been dropped from a height therefore its initial velocity becomes zero

So we can apply, S=ut +0.5 at square

20=0*t+0.5 10*t square

4 =t square

T =2

Answer 2

Answer:

Please mark brainliest

Explanation: