Question

A battery of emf 12 V and internal resistance 3 ohm is connected to a resistor. If the current in the circuit is 0.5 A, a. Calculate resistance of resistor. b. Calculate terminal voltage of the battery when the circuit is closed. c. What is the maximum current that can be drawn from the cell. ​

Answer 1

Answer:

Explanation:

Given: A battery of emf 10V and internal resistance 3Ω is connected to a resistor. The current in the circuit is 0.5A

To find the terminal voltage of the battery when the circuit is closed

Solution:  

Emf of the battery, E=10V

Internal resistance of the battery, r=3Ω

Current in the circuit, I=0.5A

Resistance of the resistor = R

The relation for current using Ohm's law is,

I=  E /R+r

⟹R+r=  E/I

​⟹R+r=  10 /0.5

⟹R=20−3=17Ω

Terminal voltage of the resistor = V

According to Ohm's Law,

V=IR

⟹V=0.5×17

⟹V=8.5V

Therefore, the resistance of the resistor is 17Ω and the terminal voltage is 8.5V

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