Question

A battery of emf 15V and internal resistance 3ohm is connected to two resistors of 3ohm and 6ohm connected in parallel find (1)the current through the battery,(2)p.d.between the terminals,(3)the current in 3ohm resistor and(4)the current in 6ohm resistor.​

Answer 1

Answer:

V=I*R

15=I*0.5

I=30A

for 3ohm

V=I*R

15=I*3

5=I

SINCE CONNECTED IN PARALLEL

6OMH

WILL BE

30-5=15A