Question

a battery of EMF 2 volt and internal resistance 1 ohm is used to send a current through a potentiometer wire of length 200 cm and resistance 4 ohm what length of the wire will be required to balance a cell of EMF 1.08 volt​

Answer 1

Answer:

ANSWER

I=

R

V

=

10+20

6

=

30

6

=

5

1

A

Voltage across wire =6−

5

1

×10

=4V

Voltage per unit length =

200

4

=0.02v/s

Length for balancing =

2

2.4

×100cm

=120cm

Answer 2

Length of Balancing is 120 cm......