Question

A battery of emf of 24.0 V and internal resistance of 4.0 ohms is connected to resistance of 32 ohms. What is the potential difference of the battery?

Answer 1

V=IR

so taking R=32+4=36 ohms

and V=24V

I=V/R

I=24/36

I=2/3 A

now taking this I

and internal resistance of 4 Ohms

V=2/3*4

V=8/3 or 2.66 (approx)