Question

find the square root ofgiven polynomial 36x⁴-96x³-16x-76x²+1 by division method​

Answer 1

Answer:

i) x4 −12x3 + 42x2 −36x + 9

Step 1 :

x4 has been decomposed into two equal parts x2 and x2.

Step 2 :

Multiplying the quotient (x2) by 2, so we get 2x2. Now bring down the next two terms -12x3 and 42x2.

By dividing -12x3 by 2x2, we get -6x. By continuting in this way, we get the following steps.

Hence the square root of x4 −12x3 + 42x2 −36x + 9 is x2 - 6x + 3

(ii) 37x2 −28x3 + 4x4 + 42x + 9

Solution :

First let us arrange the given polynomial from greatest order to least order.

4x4 −28x3 + 37x2 + 42x + 9

Hence the square root of 37x2 −28x3 + 4x4 + 42x + 9 is 2x2 - 7x - 3.

(iii) 16x4 + 8x2 + 1

Solution :

Hence the square root of 37x2 −28x3 + 4x4 + 42x + 9 is 4x2 + 0x + 1.

(iv) 121x4 − 198x3 − 183x2 + 216x + 144

Step-by-step explanation:

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