A battery of two cells having potential difference 1.5 V each is used to light a bulb of resistance 5 ohm? how much current will flow through the bulb?
Answers
Answered by
39
Given : Battery is made up of two cells of 1.5 volt of potential differences. This battery is used to light a bulb of 5Ω.
To find : Amount of current flowing through the bulb
Solution :
This question can be solved by using the concept of ohm's law. Which states that voltage of the conductor is directly proportional to the current flowing through the conductor. Resistance is taken as a constant value.
i.e.
>> V = IR
Total voltage of battery = voltage of cell 1 + voltage of cell 2
Total voltage v = 1.5 + 1.5 = 3 v
adding given values of V and R in this equation::
>> 3 v = I (5Ω)
>> 3v / 5Ω = I
>> 0.66 Ampere = I [ Voltage/ohm is equal to Ampere]
0.66 Ampere is the required value of current flowing through the bulb.
Similar questions