Question

A BC Fer5y has an acceleration of 0.50 m/s 2 . If the ferry travels 125m in 20 seconds while

accelerating, what was its initial velocity?

Answer 1

Answer:

1.25 m/s

Explanation:

• Accelaration(a) = 0.5 m/s²
• Distance Travelled(s) = 125 m
• Time taken (t) = 20 sec
• Initial Vocity(u) = ?

Second Equation Of motion :-

$\color{red}{s = ut+\frac{1}{2}at²}$

Lets Put the values :-

$=>125= (u\times 20)+(\frac{1}{2} \times 0.5 \times 20 \times 20) \\ => 125 = 20u + 100 \\ => 125 - 100 = 20u \\ => 25 = 20u \\ =>u = \frac{25}{20} \\ => \boxed{1.25}$

Hope it helped