Question

A beaker containing 0.01 mole of sugar in 100g water and a beaker containing 0.02 mole of sugar in 100g water are placed in a chamber and allowed to equilibriate. What is the mole fraction of sugar in the resulting solution.

Answer 1

Given:

The no of moles of sugar in solution 1, n1 = 0.01

The mass of water in solution 1, W1 = 100 gm

The no of moles of sugar in solution 1, n2 = 0.02

The mass of water in solution 1, W2 = 100 gm

To Find:

The mole fraction of sugar in the resulting solution.

Calculation:

- The total no of moles of sugar, n = n1 + n2

⇒ n = 0.01 + 0.02

⇒ n = 0.03

- The total mass of water, W = W1 + W2

⇒ W = 100 + 100

⇒ W = 200 gm

- The no of moles of water, N = 200/18

⇒ N = 11.11

- The mole fraction of sugar, X = n/(n + N)

⇒ X = 0.03/(0.03 + 11.11)

⇒ X = 0.03/11.14

⇒ X = 0.0027

- So, the mole fraction of sugar in the resulting solution is approximately 0.0027.